Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
How many jumps is it from the decimal point to the position to the right of the 6
The answer to that is 3 jumps. Since the move of the decimal made the number larger than it really is, it will take a negative value to put it back where it belongs.
So A) is the correct answer. It is in scientific notation and if you move the decimal back 3 place you get the number you stared with.
The sum of 10 and a subtraction of 4 from 6.
Answer:
2.275%
Step-by-step explanation:
The first thing to do here is to calculate the z-score
Mathematically;
z-score = (x-mean)/SD
from the question, x = 12,300 hours , mean = 11,500 hours while Standard deviation(SD) = 400 hours
Plugging the values we have;
z-score = (12,300-11,500)/400 = 800/400 = 2
Now, we want to calculate P(z ≤ 2)
This is so because we are calculating within a particular value
To calculate this, we use the z-score table.
Mathematically;
P(z ≤ 2) = 1 - P(z > 2) = 1 - 0.97725 = 0.02275
To percentage = 2.275%
2^5/2^2 = 2^(5-2)
= 2^3
= 8
