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attashe74 [19]
3 years ago
10

Please help math 3 in highschool

Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer:

The graph

Step-by-step explanation:

f(2) for the graph is 8

f(2) for the function is -22

8 is greater than -22

therefor, the graph has the larger value for x = 2

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y  , 8 z>

Δf = λ Δh

So

< 8 ,8 , 4> = < 8  λ x ,8 λ y  , 8 λ z>

8 = 8  λ x                     -------------1

8 = 8 λ y                      ----  ------2

4 = 8 λ z                    ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36

So the value of λ is

\lambda =\pm \dfrac{1}{2}

When λ = 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0
3 years ago
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To add integers with the same sign
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Arithmetic

-3-2=5

because

-3-2

=

-3 + -2

3 negatives + 2 negatives = 5 negatives

5 0
3 years ago
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(3m^3- 1/2 y) (3m^w - 1/2y)<br> multiply
Westkost [7]

Answer:

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4 0
3 years ago
. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS
trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

\sqrt{17^{2}-15^{2}} = RP

RP=\sqrt{289-225}

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = \frac{1}{2} (30) (33) = 495 meter²

6 0
3 years ago
Kyla put 4 ounces of milk in 2 cups of coffee for her parents. How much milk would she need for 16 cups of coffee?A: 1cB: 1qtC:2
Ronch [10]

Kyla put 4 ounces of milk in 2 cups of coffee for her parents. How much milk would she need for 16 cups of coffee?



A: 1c

B: 1qt

C:2c

D:2qt​

______________

4 ounces of milk in 2 cups of coffee for her parents.

4/2= 2 ounces of milk per cup

___________________

for 16 cups

Do you know how many ounces correspond to c or qt?

16* 2= 32 ounces

________________

32 ounces = 1 qt

So then,

Kyla needs to put 1 qt for 16 cups of coffee

Answer: B 1 qt

Do you have any questions regarding the solution?

If you don’t need further explanation on this question, we can end the session.

I want to remind you this answer will always be saved in your profile. I’d really appreciate you letting me know how I did by rating our session after you exit. Thanks and have a great day!

7 0
1 year ago
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