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KatRina [158]
3 years ago
8

Hey plz help i’ve been stuck

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

Um, I just see a black square! Maybe could you try reuploading a picture?

Step-by-step explanation:

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A closed cylindrical can of fixed volume V has radius r.a) Find the surface area, S, as a function of r.b) What happens to the v
andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if  V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = \frac{10}{\pi r^{2}}

By placing the value of h in the formula of surface area,

S = 2\pi r(r+\frac{10}{\pi r^{2}})

Now we can get the points to plot the graph,

r       -2             -1         0       1            2

S    -13.72     -13.72     0    26.28    35.13

7 0
3 years ago
PLEASE ANSWER PLZZZ HELP
stich3 [128]
0.0307 or what are you giving us here?
3 0
3 years ago
What is 15 times 0.85?
Fofino [41]

Answer:

12.75

Step-by-step explanation:

You multiply 15.00 into 0.85

7 0
3 years ago
Can anyone help!<br> WITH STEPS!
MissTica

Answer:

When we have something like:

\sqrt[n]{x}

It is called the n-th root of x.

Where x is called the radicand, and n is called the index.

Then the term:

\sqrt[4]{16}

is called the fourth root of 16.

And in this case, we can see that the index is 4, and the radicand is 16.

At the end, we have the question: what is the 4th root of 16?

this is:

\sqrt[4]{16} = \sqrt[4]{4*4}  = \sqrt[4]{2*2*2*2} = 2

The 4th root of 16 is equal to 2.

6 0
3 years ago
Pleaseeeeeeeeeeeee help me!!!!!
Aneli [31]
Answer is 150/x see photo for solution

4 0
3 years ago
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