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Nikitich [7]
2 years ago
10

Exponential Growth and Decay The expressions below represent either exponential growth or exponential decay. Check all the expre

ssions that represent exponential decay. 5x 3(0.75)2t 35(2.4)x 5000(1.04)3t 0.05x 500(0.005)t
Mathematics
2 answers:
Tomtit [17]2 years ago
5 0

Answer:

First one: 5x3(0.75)2t

and fourth one: 0.05x500(0.005)t

Step-by-step explanation:

In order to have an exponencial decay, the rate of the exponencial function needs to be lesser than 1.

The rate is the value between parenthesis, so in the first equation, the rate is 0.75, so this is an exponencial decay.

The second equation has rate = 2.4, so this is not an exponencial decay.

The third equation has rate = 1.04, so this is not an exponencial decay.

The fourth equation has rate = 0.005, so this is an exponencial decay.

kykrilka [37]2 years ago
5 0

Answer:

It's A,C,F

Step-by-step explanation:

I answered it :) and got it right.

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A beverage is made by mixing 1 part of water with 3 parts of fruit juice. How many parts of water are mixed with 1 part of fruit
forsale [732]

Answer:

1/3

Step-by-step explanation:

for every 1 part of water there is 3 parts juice so if there's only 1 part juice it would be a 1/3

5 0
2 years ago
Read 2 more answers
Help me find the solution set for 8x-3=2(x-1/2)
daser333 [38]
8x -3 = 2(x-1/2)
⇒ 8x -3= 2x -2*(1/2)
⇒ 8x -3 = 2x -1
⇒ 8x -2x= -1+ 3
⇒ 6x = 2
⇒ x= 2/6
⇒ x= 1/3

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3 years ago
Please help homework due
jolli1 [7]

Answer:

X≤3

Step-by-step explanation:

This is because the arrow is moving down the number line

3 0
2 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
2 years ago
5s=13 what is the answer
Alisiya [41]
S= 13/5 is the answer
I hope it’s help u !
8 0
1 year ago
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