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BartSMP [9]
3 years ago
11

Fill in the table using the function rules

Mathematics
2 answers:
Alla [95]3 years ago
6 0
1. 25
2. 22
3. 19
4.16
Blizzard [7]3 years ago
6 0
1 = 25 2=22 3=19 4=16

I provided a photo of the work. You have to plug-in the numbers into the x. (View photo as reference)

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Pls answer :c ! I need help ASAP ! (Math)
kaheart [24]

Answer:

6x = 12 : Divide both sides of the equation 6

6 ( x - 12 ) = -3x - 5: Distrubite the 6 to clear the paranthesis

6x + 5 = 9x - 1 : Subtract 6 from both sides of the equation

5 0
3 years ago
De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

7 0
3 years ago
Question is below in picture
Ivan
It's x^{2} +6x+1
/x(x+2)because this choice made the most since.
4 0
3 years ago
Find the greatest common factor. Show work!
zvonat [6]

Answer:

4y

Step-by-step explanation:

Because it is the GCF of the numbers and it can't have an exponent since 16y has none.

3 0
3 years ago
PLS HELP FAST I NEED IT
Gemiola [76]

Answer:

(b) 1:9

(c) 1:8

Step-by-step explanation:

(b) x*y : kx*ky, so 1:k² with k=3 is 1:9

(c) Assuming the rectangles get a z dimension, the volumes would have a ratio of xyz : xkykzk = xyz : xyzk³ = 1 : k³. With k=2 that is 1:8. But the z was never introduced so this is a bit inconclusive.

3 0
3 years ago
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