Hello there the answer to your question would be 60. Since 150-(60%*150) = 150 - 60 *150 = (1-60%)*150 = (100%-60%) * 150= 40% * 150 = 40/100 * 150 = 40 * 150 ÷ 100 = 6000/100 = 60. Hope this helps you out, have a great day!
Answer:
Number of cheaper dresses sold is 35
Number of expensive dresses sold is 15
Step-by-step explanation:
Given:
Cost of cheaper dresses = $90
Cost of expensive dresses = $140
Total cost of the dresses = $5250
To Find:
Number of cheaper dress = ?
Number of expensive dress = ?
Solution:
Let
The number of cheaper dresses be x
The number of expensive dresses be y
(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250
= $5250
It is given that the 20 more of the cheaper dresses than the expensive dresses is sold
So,
number of cheaper dress = 20 + number of expensive dress
x = 20 + y---------------------------------------(1)







y = 15
Substituting y in (1)
x = 20 +15
x= 35
Answer:
plug in -6
-(-6) - 3
the 6 turns into a positive
subtract 3 from 6
= 3
Answer:
solution is (- 3, 5 )
Step-by-step explanation:
given the 2 equations
6x - y = - 23 → (1)
8x + 3y = - 9 → (2)
rearrange (1) expressing y in terms of x
y = 6x + 23 → (3)
Substitute y = 6x + 23 into (2)
8x + 3(6x + 23 ) = - 9
8x + 18x + 69 = - 9
26x + 69 = - 9 ( subtract 69 from both sides )
26x = - 78 ( divide both sides by 26 )
x = - 3
substitute x = - 3 into (3)
y = (6 × - 3 ) + 23 = - 18 + 23 = 5
solution is (- 3, 5 )
Answer:
If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y
∴ $1*(x*1) + $2*(y*1) = $13
Step-by-step explanation:
1) You can buy 4 brownies for $2 each = 2*4 = $8
The rest you can buy cookies = 5 cookies = $5
$8+$5=$13
2) You can buy 5 brownies and 3 cookies = $10+$3 = $13
3) You can buy 3 brownies and 7 cookies = $6+$7=$13
Equation: -
If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y
∴ $1*(x*1) + $2*(y*1) = $13