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defon
2 years ago
11

What is the common difference of the following sequence: -6, -2, 2, 6

Mathematics
1 answer:
dexar [7]2 years ago
8 0

Step-by-step explanation:

take 6-2 to get 4

4 is your common difference for ex.

-6+4 = -2

-2+4=2

2+4=6. You have to two pick an easier numbers out of the problem to find your common difference. Then check your answer to make sure it is right.

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Every year Ethan ears 38,428. Every year he spends 21,728 on expenses. How much money should Ethan have leftover?
svlad2 [7]

Answer:

16,700

Step-by-step explanation:

38,428

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21,728

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16,700

4 0
3 years ago
Make d the subject of the formula h=<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B3%7D" id="TexFormula1" title="\frac{d}{3}
lakkis [162]
First you would subtract 2 to get d/3 by itself. On the left side you would have h-2 and one the right d/3 (h-2=d/3). Then you divide by 3 to get d by itself. So the answer is h/3-2/3=d
4 0
3 years ago
HELP WITH THESE QUESTIONS PART 2... 1 Question
Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

csc = \frac{hypotenuse}{opposite} = \frac{\sqrt{10}}{3}

sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

cot = \frac{adjacent}{opposite} = \frac{1}{3}

7 0
3 years ago
Should students learn alternate interior angles in 8th grade
Taya2010 [7]
Yes students should be learning interior angles in 8th grade
5 0
3 years ago
Please hurry, thank you!!!
MatroZZZ [7]
(-1/2)^-4
=16

the last one
5 0
3 years ago
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