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Shkiper50 [21]
3 years ago
9

A cruise ship is currently 20 kilometers away from its port and is traveling away from the port at 5 kilometers per hour . The f

unction is y=5x +20 relates the number of kilometers y the ship will be from its port x hours from now. How far will the cruise ship be from its port 3 hours from now
Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

You can do this. It's actually pretty simple

Step-by-step explanation:

You are given 3 hours. and you re told 5 kph or kilometres per hours.

3 replaces the x variable. You can take it from there and for sure you'll get the answer you want for y

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If half a gallon of milk is 3 dollars then you should be able to buy one gallon for 6 dollars. Therefore 5 dollars can buy 5/6 gallons of milk.
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The circumference is 6π

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Answer:

Each bike with both types of tire.

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This will allow to compare the tires wear in equal conditions. If the tires are assigned randomly to the volunteers, there will be difference in the wear due to difference habits of the bikers.

The only way to implement a matched-pair test with bikes is to use one type of tire in the front wheel and the other type in the rear wheel. Half of the tires of each type will be in the front and half in the rear.

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Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out
Andrews [41]

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

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Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

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