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Angelina_Jolie [31]
3 years ago
11

The x values are the

Mathematics
1 answer:
dem82 [27]3 years ago
4 0
The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"
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Two numbers multiply to be -50 and add to 0
sineoko [7]

Clever !

The two square roots of  50  will do that.
They are irrational numbers, so I can't write down their exact values.
They are approximately  +7.0711  and  -7.0711  (rounded) .

3 0
2 years ago
Please help 8th grade math
Zepler [3.9K]

Answer:

1500 calories

Step-by-step explanation:

2400 is 100% of in this case, 8/8

So then we know that 1/8 of 2400 is 300 because we just divide it by 8. Sarah eats 5/8 that much so we multiply 300 by 5 which gives us 1500

6 0
2 years ago
Read 2 more answers
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Novay_Z [31]

Answer:  3+\sqrt{2}

Step-by-step explanation:

Given the following expression shown in the picture:

\frac{7}{3-\sqrt{2} }

You need to use a process called "Ratinalization".

By definition, using Rationalization you can rewrite the expression in its simplest form so there is not Radicals in its denominator.

Then, in order to simplify the expression, you can follow the following steps:

<em>Step 1</em>. You need to multiply the numerator and the denominator of the fraction by  3+\sqrt{2}, which is the conjugate of the denominator  3-\sqrt{2}.

<em>Step 2</em>. Then you must apply the Distributive property in the numerator.

<em>Step 3</em>. You must apply the following property in the denominator:  (a+b)(a-b) = a^2 - b^2

Therefore, applying the procedure shown above, you get:

=\frac{(7)(3+\sqrt{2})}{(3-\sqrt{2})(3+\sqrt{2})}=\frac{21+7\sqrt{2}}{3^2-(\sqrt{2})^2}=\frac{21+7\sqrt{2}}{9-2}=\frac{21+7\sqrt{2}}{7}

<em>Step 4</em>.  You can observe that the expression can be simplified even more. Since:

 \frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

You get:

\frac{21+7\sqrt{2}}{7}=\frac{21}{7}+\frac{7\sqrt{2}}{7}=3+\sqrt{2}

3 0
2 years ago
HELP ASAP I WILL GIVE BRAINLIST ( I HAVE ANSWERED #1 SO MOSTLY NEED THE ANSWER TO #2 )
Black_prince [1.1K]

Answer:

2) Constraints can be used to model different variables that cannot equal zero. They can be used in many different cases. For example, modeling money or a ball being dropped.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r &lt; d. n = −67, d = 8
Firlakuza [10]

Answer:

q = 8

r = 3

Step-by-step explanation:

Given

n = dq + r

0 \le r < d

n = 67 --- not -67

d = 8

Required

Find q and r

Substitute values for d and b

n = dq + r

67 = 8 * q + r

67 = 8q + r

Make q the subject

q = \frac{67 - r}{8}

0 \le r < d means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let r = 3

q = \frac{67 - 3}{8}

q = \frac{64}{8}

q = 8

No other true values of r and q can be gotten.

7 0
3 years ago
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