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densk [106]
2 years ago
9

A baseball “diamond” is a square with a side length of 90 feet. How far is the throw from

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
7 0

Answer:

127

Step-by-step explanation:

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2. David determines that 3 sqrt 2 cis(7pi/4) = -3+3i. When he considers the graphical representation of these numbers, he knows
fiasKO [112]

The correct rectangular equivalence of 3sqrt(2)·cis(7pi/4 ) is:

3sqrt(2)·cos( 7pi/4 ) + i·sqrt(2)·sin( 7pi/4 )  =  3 - 3i.

<h3>Where did David go wrong?</h3>

David mistakenly interchanged the Sin function and the Cos function when he was calculating the problem.

Hence the correct rectangular equivalence is:

3sqrt(2)·cos( 7pi/4 ) + i·sqrt(2)·sin( 7pi/4 )  =  3 - 3i.

<h3>What is rectangular equivalence?</h3>

An equation is rectangular in form when it is comprised of Variables like X and Y and can be represented on a Cartesian Plane.

Learn more about rectangular equivalence at:
brainly.com/question/27813225
#SPJ1



5 0
1 year ago
F(x)= -x over x^2+5 on the domain [0,4]
BartSMP [9]
If you're asking for extrema, like the previous posting

well

\bf f(x)=\cfrac{-x}{x^2+5}&#10;\\\\\\&#10;\cfrac{df}{dx}=\cfrac{(x^2+5)+2x^2}{(x^2+5)^2}\implies \cfrac{df}{dx}=\cfrac{5+3x^2}{(x^2+5)^2}\impliedby &#10;\begin{array}{llll}&#10;using\ the\\&#10;quotient\ rule&#10;\end{array}

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points

and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4

f(0) = 0        <---- only maximum, and thus absolute maximum

f(4) ≈ - 0.19  <----  only minimum, and thus absolute minimum
5 0
3 years ago
Is the binomial a factor of the polynomial function?
olchik [2.2K]

Answer:

YES

NO

NO

Step-by-step explanation:

The given polynomial is: $ f(x) =  x^3 + 4x^2 - 25x - 100 $

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

        = 125 + 100 - 125 - 100

        = 225 - 225

        = 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

      = -8 + 16 + 50 - 100

     = -108 + 66

     ≠ 0

Therefore, (x  + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

        = 64 + 64 - 100 - 100

        = 128 - 200

        ≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0
3 years ago
Please check my question. 11 points. thanks for the help.
n200080 [17]
Its right.................
7 0
3 years ago
|x+11| =−1<br> plz help show steps 2
dezoksy [38]

Answer:

No solutions. You can’t have a negative absolute value.

3 0
3 years ago
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