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PIT_PIT [208]

3 years ago

le="( {81}^{ \frac{1}{4} } )^{4} " alt="( {81}^{ \frac{1}{4} } )^{4} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Sveta_85 [38]3 years ago

7 0

If you're asking how to simplify, then this is how you do it.

when a power meets another power but in brackets, then you have to multiply the powers. ¼ × 4 would be 1. i simplified 81 to 3⁴.

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Lori has nine hours to spend this weekend working on a dozen art projects. If she splits her time evenly how long will she work

zloy xaker [14]

Answer:

4 hours and 30 min every day

Step-by-step explanation:

2 days in weekend so 4 hour and 30 times two is 9 hours your welcome

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3 years ago

Adult red wolves vary in length from 137.16 cm to 168.64 cm. Estimate the difference in length between the longest and shortest

zhannawk [14.2K]

Answer:

As per the statement:

Adult red wolves vary in length from 137.16 cm to 168.64 cm.

To find the difference in length between the longest and shortest of these wolves.

Longest length of wolves = 168.64 cm

Shortest length of wolves= 137.16 cm

Then;

$\text{Difference of the length between the longest and shortest of these wolves}$ = $\text{Length of longest wolves} -\text{Length of shortest wolves}$

Substitute the given values we have;

$\text{Difference of the length between the longest and shortest of these wolves}$ = 168.64 - 137.16 = 31.48 cm

therefore, the difference in length between the longest and shortest of these wolves is 31.48 cm

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3 years ago

You are having a wedding anniversary party. In attendance are a grandfather, a grandmother, two fathers, two mothers, four child

Zepler [3.9K]

After counting, there are 23 people in attendance. If each person is eating two burgers:

$23*2=46$

You'll need at least 46 burgers.

8 0

3 years ago

Part I: Measuring Parts of a Circle

cluponka [151]

Answer:

case a) The approximate circumference of circle is $5.9\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=2.95$

case b) The approximate circumference of circle is $6\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3$

case c) The approximate circumference of circle is $6.24\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3.12$

Step-by-step explanation:

we know that

The approximate circumference of each circle, is equal to the perimeter of each inscribed polygon

case A) the figure is an inscribed pentagon

step 1

Find the approximate circumference of circle

The perimeter of the pentagon is equal to

$P=5s$

where

$s=1.18\ units$

substitute

$P=5(1.18)=5.9\ units$

therefore

The approximate circumference of circle is $5.9\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=5.9/2=2.95$

case B) the figure is an inscribed hexagon

step 1

Find the approximate circumference of circle

The perimeter of the hexagon is equal to

$P=6s$

where

$s=1\ units$

substitute

$P=6(1)=6\ units$

therefore

The approximate circumference of circle is $6\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6/2=3$

case C) the figure is an inscribed dodecahedron

step 1

Find the approximate circumference of circle

The perimeter of the dodecahedron is equal to

$P=12s$

where

$s=0.52\ units$

substitute

$P=12(0.52)=6.24\ units$

therefore

The approximate circumference of circle is $6.24\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6.24/2=3.12$

Conclusion

We know that

The exact value of the ratio $\frac{C}{D}$ is equal to

$\frac{\pi D}{D}=\pi$

The approximate value of the circumference will be closer to the real one when the number of sides of the inscribed polygon is greater

4 0

3 years ago

3 1/9+2 1/4= what is the answer

34kurt

Answer:
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Step-by-step explanation:

3 0

3 years ago