All categories

3 years ago

I need some help with this question, I got a different answer.

Mathematics

1 answer:

N76 [4]3 years ago

5 0

Answer:

The median is the middle number.

Step-by-step explanation:

You have to order the numbers from least to greatest, or greatest to least, and choose the number in the middle. Since there is an even number of values, you have to take the mean of the two middle numbers. I hope this helps.

You might be interested in

-12+8yi=3x-i solve for x and y

kodGreya [7K]

Answer:

x = -4 + 8yi/3 + i/3, y = -3xi/8 - 1/8 - 3i/2

3 0

3 years ago

The radius of the circle above is 34 mm. What is the circumference of the circle? (Use 7 = 3.14.)

Ratling [72]

213.52 mm because you have to use the formula (c=2*pi*r). First, you multiply 2 by 3.14, which is 6.28. Then, you multiply 6.28 by the radius,34, and you get 213.52 mm. Hope this helped!!!

7 0

2 years ago

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd

mestny [16]

Answer:

1) $P(X = 8) = 0.1033$

$P(X = 9) = 0.0688$

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So $\mu = 6$ .

P(X = 8)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033$

P(X = 9)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688$

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.1033 = 20.66$

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.0688 = 13.76$

8 0

3 years ago

Summarize everything you know about exponential functions

Annette [7]

A function with a positive constant other than 1 raised to a variable exponent is known as an exponential function. As a function is evaluated, it is solved at a given input value. Where the growth rate and initial value are known, an exponential formula can be used.

Sorry I dont know much about them but I hope this helps you!!

6 0

2 years ago

Abs(sin(x) - sin(y)) ≤ abs(x-y)

barxatty [35]

3 0

3 years ago