The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Because they have the same inclination so if we try to draw them on a diagram they will be parallel to each other.
The sides
12-3a
12-3a
4(2a-5)=8a-40
so for perimeter we + them
(12-3a)+(12-3a)+(8a-40)
=
2a-16
1/4 times 2 2/3 = 2/3
Change from a mixed number to improper fraction: 1/4 times 8/3
Multiply across so 1x8/4x3 to get 8/12
Simplify to 2/3
Answer:
C/3rd one. (y=2x+4)
Step-by-step explanation:
In the equation y=mx+b, m=slope of the line and b=y-intercept. From the graph, we know the y-intercept is 4 so we can write y=mx+4. To find the slope: (0-4)/(-2-0) = (-4)/(-2) = 2. We can replace the m with 2 to get the final equation of y=2x+4 which is also the third answer.
