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Pani-rosa [81]
3 years ago
5

What is sin θ given (–3, 4) is a point on the terminal side of θ?

Mathematics
1 answer:
Ber [7]3 years ago
5 0

Answer:

QUESTION 1-  sin\theta =-\frac{4}{5}

QUESTION 2-  cos\theta =-\frac{5}{\sqrt{14} }

QUESTION3- sinx =-\frac{1}{\sqrt{17} }

Step-by-step explanation:

For Question 1

From the given point(-3,4), we can deduce the following.


The point is in the 2nd quadrant.

The right-angled triangle which is formed has a hypotenuse of length 5 by Pythagoras theorem whrere B=3 and P=4.


The third quadrant are from 90° to 180° in which the angle lie.

so  sin\theta =-\frac{P}{H}=-\frac{4}{5}


For Question 2

From the given point(-4,-5), we can deduce the following.


The point is in the 3rd quadrant.

The right-angled triangle which is formed has a hypotenuse of length  \sqrt{14} by Pythagoras theorem whrere B=-4 and P=-5.

The third quadrant are from 180° to 270° in which the angle lie.

so  cos\theta =-\frac{P}{H} =-\frac{5}{\sqrt{14} }


For Question 3

The line with equation 4b + a = 0 , we can deduce that the value of b=-\frac{a}{4}

slope of line  tan\theta =-\frac{P}{B} =-\frac{1}{4}

Hypotenuse of length \sqrt{17} by Pythagoras theorem whrere B=4and P=1.

so  sinx =-\frac{P}{H} =-\frac{1}{\sqrt{17} }.


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