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Daniel [21]
3 years ago
11

Tue or False? The first distribution shown below had a smaller mean than does the second distribution

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

the answer id true

i hope that helps

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Express each number in standard form.
Vitek1552 [10]

a) 1,000 + 0 + 40 + 9

b) 40,000 + 3,000 + 800 + 70 + 0

c) 8,000,000 + 100,000 + 5

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A movie membership costs $10 a month plus an additional $5 for each movie purchased. If you have only budgeted to spend a maximu
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3

Step-by-step explanation:

25-10/3=3

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Which statement best applies to the function y = x squared?
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Answer:

b.  The range only includes numbers greater than or equal to 0.

Step-by-step explanation:

Any square of a number will never lead to a negative number

The range of an equation is it's numerical possibilities for y

Since a square of a negative number never leads to a negative y

The answer is therefore, the range can only be zero and above

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What types of units are used to describe area
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The mean life span of a brand name tire is 50,000 miles. Assume that the life spans of the tires are normally distributed, and t
Vlada [557]

Answer:

a) P(X

b) P(\bar X>50200)=1-0.994=0.0062  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the mean life span of a brand name tire, and for this case we know the distribution for X is given by:

X \sim N(\mu=50000,\sigma=800)  

Part a

We want this probability:

P(X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

Part b

Let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(50000,\frac{800}{\sqrt{100}})

We want this probability:

P(\bar X>50200)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >50200)=1-P(Z

P(\bar X>50200)=1-0.994=0.0062  

3 0
2 years ago
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