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3 years ago

Tue or False? The first distribution shown below had a smaller mean than does the second distribution

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

the answer id true

i hope that helps

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A school photography company allows parents to purchase fractions of portrait packages. Parents can select only the pictures the

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2 years ago

Traveling at 65 mph how many feet can you travel in 22 minutes?

baherus [9]

If you are travelling at 65 mph, you have to think of it as if you are moving at a constant speed. By dividing 65 by 60, you are calculating how many miles you are moving each minute. In doing so, you can calculate that you are moving at 1.083333 miles each minute. That's approximately 5720 feet per minute. (This is calculated by multiplying 1.083333 by 5280 (the number of feet in a mile)). 5720 x 22 minutes, you will have traveled 125,840 feet.

Hope this helps!

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2 years ago

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BRAINIEST TO WHIVER RIGHT HELP

Alex Ar [27]

The least value is the smallest number in a set. So in this case it would be 3 since the first marker marks 3 on the box plot.

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2 years ago

A = 5<br> an + 1 = 24, -7

iragen [17]

You need to use recursive sequence for this one

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2 years ago

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Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se

sertanlavr [38]

Answer:

The volume of the solid is: $\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

Step-by-step explanation:

GIven that :

$y = 2 + sec \ x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \ y \ = 2$

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid can be calculated as follows:

$V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx$

$V = \pi [4x - tan \ x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})] \\ \\ \\ V = \pi [8(\dfrac{\pi}{3}) - 2 \ tan (\dfrac{\pi}{3}) ]$

$\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

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2 years ago