Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
First, we obtain the gradient (slope) of the first parallel line
Recall that since both lines are parallel, we have that,
Thus
Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)
Using
I forgot about this one!! I lbew but I lost it!! Sorry :(
Answer:
a
Step-by-step explanation:
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Answer:
x = 1/3, x = -1.
Step-by-step explanation:
2x(x + 2) + (x - 1)² = 2
Distribute the 2x into x + 2.
2x² + 4x + (x - 1)² = 2
Square (x - 1).
2x² + 4x + x² - x - x + 1 = 2
Combine terms.
2x² + x² + 4x - 2x + 1 = 2
Combine terms again.
3x² + 2x + 1 = 2
Subtract 2 from both sides.
3x² + 2x - 1 = 0
Factor.
(3x - 1)(x + 1) = 0.
Finding the x-values here is the same thing as finding the 0s, so set both of the expressions to 0.
3x - 1 = 0
Add 1 to both sides.
3x = 1
Divide by 3.
x = 1/3.
x + 1 = 0
Subtract 1 from both sides.
x = -1.
