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densk [106]
3 years ago
12

Find the common ratio of the geometric sequence -7,-14,-28

Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Aneli [31]3 years ago
7 0

Answer:

2

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

-14/-7 = 2

Check by dividing the third term by the second term

-28/-14 = 2

The common ratio is 2

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Simplify the expression (-x)^5(4x)^2?<br>A)-16x^7<br>B)-16x^10<br>C)-8x^7<br>D)16x^10
zhenek [66]
The answer is c. i hope that helpped
7 0
3 years ago
What is the volume of the right triangular prism? Round to the nearest tenth.
Tatiana [17]

Answer:

613.8 meters cubed

Step-by-step explanation:

6.2x11x9=exactly 613.8 meters cubed

4 0
3 years ago
Read 2 more answers
8. What is m&lt;1<br> 77<br> 1<br> 56<br> A 103°<br> | C 133°<br> C °<br> D 124°<br> B 47°
saveliy_v [14]

Answer:

Option C

Step-by-step explanation:

Exteriore angle property: Exterior angle equals the sum of opposite interior angles.

∠I = 77° + 56°

    = 133°

5 0
2 years ago
Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605

Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: \lambda=2\cdot 2.1=4.2

P(X\geq 5)=1-P(X

Therefore, the probability is P=0.410.

4 0
3 years ago
A restaurant sends customers in their loyalty program a coupon for a free birthday dessert. suppose that 8% of
strojnjashka [21]

Answer:

Not normal, because we expect fewer than 10 children to redeem the coupon.

Step-by-step explanation:

7 0
2 years ago
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