Answer:
Option D = 3.4 g/mL
Explanation:
Given data:
Volume of water = 21.2 mL
Volume of water + object = 27.8 mL
Mass of object = 22.4 g
Density of object = ?
Solution:
First of all we will calculate the volume of object.
Volume of object = Volume of water+ object - volume of water
Volume of object = 27.8 mL - 21.2 mL
Volume of object = 6.6 mL
Density of object:
d = m/v
d = 22.4 g/ 6.6 mL
d = 3.4 g/mL
Explanation:
The non living things in its environment is called a " matrix,"
A matrix is what supports a non living thing to reproduce, triple its existence & reproduce in mass quantities, like soil bacteria, and others..
Answer:
Coasts are sensitive to sea level rise, changes in the frequency and intensity of storms, increases in precipitation, and warmer ocean temperatures. In addition, rising atmospheric concentrations of carbon dioxide (CO2) are causing the oceans to absorb more of the gas and become more acidic.
Nitrogen released from the breakdown of proteins is used in the synthesis of urea, which is excreted by the kidneys in the urine.
- The urea acid cycle transforms the nitrogen waste released during this process into urea, which is then excreted in the urine.
- Amino acids can be converted into energy during famine and go via the Krebs cycle.
- Muscle protein is broken down into amino acids while fasting, some of which are partially oxidized to provide energy.
- These amino acids are split up into alanine and glutamine, which are released into the circulation together with other amino acids.
- Several tissues, notably the stomach and kidney, oxidize glutamine, converting some of its carbons and nitrogen to alanine.
- The liver is where alanine and other amino acids are processed into glucose and ketone bodies and nitrogen.
learn more about urea here: brainly.com/question/14718113
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<h2>Yeast cells </h2>
Explanation:
These engineered cells will mate with each other or with normal mating type a cells, but not with normal mating type α
The sexual cell types of yeast are designated a and α, which are correspondingly conferred by the MATa and MATα alleles of the mating type locus (MAT)
Cells of opposite type can mate to establish a cell of the MATα/MATa diploid state because both MAT alleles are co-dominant, such diploid cells are sterile but can undergo meiosis and sporulation to form asci, each of which contains two MATa and two MATα haploid spores