Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Because they are all divided by 8 so you can put 2, 5, and 1 in the order so you will have:
5/8 > 2/8 > 1/8
so 5/8 is the greatest :)))
i hope this is helpful
have a nice day
Let x be the number of students that like both algebra and geometry. Then:
1. 45-x is the number of students that like only algebra;
2. 53-x is the number of students that like only geometry.
You know that 6 students do not like any subject at all and there are 75 students in total. If you add the number of students that like both subjects, the number of students that like only one subject and the number of students that do not like any subject, you get 75. Therefore,
x+45-x+53-x+6=75.
Solve this equation:
104-x=75,
x=104-75,
x=29.
You get that:
- 29 students like both subjects;
- 45-29=16 students like only algebra;
- 53-29=24 students like only geometry;
- 24+6=30 students do not like algebra;
- 16+6=22 students do not like geometry.
The correct choice is D.
