The two is in the hundreth place
Look at the number next to it, it's a five. Five rounds 2 to 3.
Your answer is 0.13
You can do this by first finding the y intercept which is the point where x = 0
-3(0) + y = 2
so y intercept is the point (0,2)
Now find the x intercept by putting y = 0
-3x = 2
x = -2/3
So we have 2 points (-2/3, 0) and (0,2) Draw a line through these 2 points and you have the required graph.
Answer:
The solution is (0, 3/4)
Step-by-step explanation:
Please copy and share the instructions. Here they are: Solve the following system of linear equations.
Both of the equations can be reduced (simplified):
2x+8y = 6 => x + 4y = 3
15x + 20y = 15 => 3x + 4y = 3
Let's use the elimination by addition and subtraction method. Multiply the first equation by -1, obtaining
-x - 4y = -3
Add the second 3x + 4y = 3
equation to the
first.
We get: 2x = 0.
Thus, x = 0. Substituting 0 for x in the 1st original equation yields:
2(0) + 8y = 6. Then y = 6/8, or y = 3/4.
The solution is (0, 3/4).
Answer:
Matt ;
Used diameter of the ball instead of Radius
Step-by-step explanation:
The volume of a sphere is given as :
4/3πr³
Radius, r = diameter / 2
Given that, the diameter = 15 cm ; The Radius = 15 / 2 = 7.5 cm
Matt made an error in his calculation by failing to covert the value of the diameter given to Radius.
By dividing the diameter by 2 = 15 / 2 = 7.5, we obtain the Radius, which is what Billy did in her own calculation.
Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1