1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erastova [34]
3 years ago
6

Can anyone help me with my math i'm really behind on it.

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

OFC babieeeeeeeee!!!!

Step-by-step explanation:

statuscvo [17]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

You might be interested in
Need help plz help!!!
yawa3891 [41]

Answer:

segment CD is congruent to segment EB

4 0
3 years ago
Surface area of a trash can plz show work
ollegr [7]

Answer:

Step-by-step explanation:

So first we need to find the area of the trash can so here is the math:

The formula:

A=LxW

Replace the letters with numbers:

8=2x4

So the area is 8 feet now we can create an equation to solve how much money it would take to make the trash can:

8x0.79=$6.32

It would take $6.32 to make the trash can

6 0
3 years ago
Which of the following is parallel to the line
valentinak56 [21]

Answer:

1

Step-by-step explanation:

h

6 0
3 years ago
Read 2 more answers
A given population proportion is .25. What is the probability of getting each of the following sample proportions
anyanavicka [17]

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )  

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

6 0
3 years ago
Find the volume of the cubes or rectangular prisms in cubic centimeters.
DanielleElmas [232]

a) Volume of Rectangular prism is \frac{36}{125}\,\,cm^3

b) Volume of cube is \frac{8}{125}\,\,cm^3

c) Volume of cube is \frac{1}{125}\,\,cm^3

d) Volume of Rectangular prism is \frac{6}{125}\,\,cm^3

Step-by-step explanation:

Part a)

Volume of rectangular prism with

length= \frac{3}{5}\,\,cm

width= \frac{4}{5}\,\,cm

height = \frac{3}{5}\,\,cm

The formula used to find Volume of rectangular prism is:

Volume\,\,of\,\,rectangular\,\,prism=length*width*height

Putting values:

Volume\,\,of\,\,rectangular\,\,prism=\frac{3}{5} *\frac{4}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{36}{125}\,\,cm^3

So, Volume of Rectangular prism is \frac{36}{125}\,\,cm^3

Part b)

Volume of cube with side length of \frac{2}{5}\,\,cm

The formula used to find Volume of cube is:

Volume\,\,of\,\,cube=length^3

Putting value of length and finding volume:

Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{2}{5})^3\\ Volume\,\,of\,\,cube=\frac{8}{125}\,\,cm^3

So, Volume of cube is \frac{8}{125}\,\,cm^3

Part c)

Volume of cube with side length of \frac{1}{5}\,\,cm

The formula used to find Volume of cube is:

Volume\,\,of\,\,cube=length^3

Putting value of length and finding volume:

Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{1}{5})^3\\ Volume\,\,of\,\,cube=\frac{1}{125}\,\,cm^3

So, Volume of cube is \frac{1}{125}\,\,cm^3

Part d)

Volume of rectangular prism with

length= \frac{1}{5}\,\,cm

width= \frac{2}{5}\,\,cm

height = \frac{3}{5}\,\,cm

The formula used to find Volume of rectangular prism is:

Volume\,\,of\,\,rectangular\,\,prism=length*width*height

Putting values:

Volume\,\,of\,\,rectangular\,\,prism=\frac{1}{5} *\frac{2}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{6}{125}\,\,cm^3

So, Volume of Rectangular prism is \frac{6}{125}\,\,cm^3

Keywords: Volume

Learn more about Volume at:

  • brainly.com/question/6443737
  • brainly.com/question/12497249
  • brainly.com/question/12613605

#learnwithBrainly

6 0
3 years ago
Other questions:
  • 5.6 - 0.105 = 5.505 What's The answer
    7·1 answer
  • A transformation of ΔDEF results in ΔD'E'F'. Which transformation maps the pre-image to the image? A. The transformation is a di
    9·2 answers
  • In a survey of zoom animals, for out of five monkeys preferred very ripe.What is this result as a percent?
    10·2 answers
  • Consider the equation 40x - 25y = 15
    11·1 answer
  • Explanation needed
    13·1 answer
  • Beforea question with division fraction she must multiply them
    15·2 answers
  • Two points from the line of best fit can be used to find the slope of the line, which can be used to find the equation of the li
    13·1 answer
  • A baseball team wins one out of every three games. How many wins<br> would they have after 27 games?
    15·1 answer
  • Jackie works as a server at a local restaurant. She makes $8 per hour. She worked 34 hours last week. She made $250 in tips. Wha
    7·1 answer
  • Area of a trapezoid 5yd, 8yd, 11yd 9yd
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!