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Julli [10]
3 years ago
8

Elimination 7x+2y = 24 (6,-9)​

Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:

7x + 2y = 24 8x + 2y = 30. Subtract -x = -6 x = 6. Substitute x = 6 into 7x + 2y = 24 7(6)+ 2y = 24 42 + 2y = 24 2y = 24 - 42 2y = -18 y = -9 {6,-9} ...

Step-by-step explanation:

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You just got a free ticket for a boat ride, and you can bring along 3 friends! Unfortunately, you have 5 friends
Makovka662 [10]

Answer:

ill split them all into halves, so at least half of everyone can come along

Step-by-step explanation:

4 0
3 years ago
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

4 0
3 years ago
How many unique triangles can be made when one angle measures 90 degrees and another angle is half that measure?
goldenfox [79]
I believe only two but im not really sure on that
7 0
3 years ago
P(2,-8), Q(8,-8), R(8, -2), S(2,-2)<br> 180° rotation<br> I need help quickly
kompoz [17]

Answer:

P(-2,8)   Q(-8,8)   R(-8,2)  S(-2,2)

Step-by-step explanation: 180 degree rotation rule = (x,y) ---- (-x,-y)

ex : point B (-2, 7) will be B' (2, -7)

6 0
3 years ago
With the beam being held still at a height of 40 m, the crane breaks and the beam falls to the ground. Assuming no air resistanc
lapo4ka [179]
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.

Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy

TE = 0 + 0

∴ TE = 0

The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
8 0
3 years ago
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