The question is not complete. The complete question is;
Triangle RST is drawn inside rectangle RSNM. Point T is halfway between points M and N on the rectangle. The length of side RS is 9 in. and the length of side RM is 8 in.
1) What is the area of triangle RST?
2)What is the ratio of area of triangle RST to area of triangle RMT?
3) What is the area of rectangle RSMN to area of triangle TSN?
Diagram is attached.
Answer:
1) 36 sq.in
2) 2:1
3) 4:1
Step-by-step explanation:
1) Area of triangle is; ½ × base × height.
For triangle RST, base = 9 in and height = 8 in
Thus, area of triangle RST = ½ × 9 × 8
= 36 sq.in
2)Area of triangle RMT = ½ × 8 × 9/2
= 18 sq.in
Ratio of area of RST to area of RMT = 36/18 = 2:1
3)Area of triangle TSN = ½ × 8 × 9/2 = 18 sq.in
Area of Rectangle RSNM = Length x width = 9 × 8 = 72 sq.in
Ratio of Area of Rectangle RSNM to Area of triangle TSN = 72/18 = 4:1
Answer:
Step-by-step explanation:
a)
Substitute limits to get
=
Thus converges.
b) 10th partial sum =
=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)