Answer:
Therefore the length of QP = 3.4 units
Step-by-step explanation:
Given:
PQ = 2x + 1
XF = 7x - 4
PF = x
Q is the mid poimt of XF
∴ XQ = QF
QF = PQ - PF ..........( Q - F - P )
= 2x + 1 - x
∴ QF = x + 1
∴ XQ = QF = x + 1
TO Find:
QP = ?
Solution:
By Addition Property we have


Substituting the given values in above equation we get
(7x - 4) + x = (x +1) + (x +1) + x
8x -4 = 3x +2
8x - 3x + 4 + 2
5x = 6
∴ 
Now we require
QP = (2x + 1)
∴ 
Therefore the length of QP = 3.4 units
Answer:
12 units²
Step-by-step explanation:
ABCD is a parallelogram.
The area (A) of a parallelogram is calculated as
A = bh ( b is the base and h the perpendicular height )
Here b = 12 and h = 1, thus
A = 12 × 1 = 12 units²
Well first all you have to do is simplifying both sides of the equation then of course isolating the variable then you should end up with

Hopefully this helps ^0^ Mark Brain