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3 years ago

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What is

Formula1" title=" \frac{1}{7} = n + \frac{5}{6} " alt=" \frac{1}{7} = n + \frac{5}{6} " align="absmiddle" class="latex-formula">

1 answer:

arsen [322]3 years ago

4 0

Well first all you have to do is simplifying both sides of the equation then of course isolating the variable then you should end up with

$n = \frac{29}{42}$

Hopefully this helps ^0^ Mark Brain

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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Debora [2.8K]

Option A

$2x^2(6x-1) + 3(6x-1)$ is one way to determine the factors of $12x^3-2x^2+18x-3$ by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

$12x^3-2x^2+18x-3$

Group the first two terms together and then the last two terms together.

$(12x^3-2x^2)+(18x-3)$

We can see that $2x^2$ is common in first two terms

And 3 is common in last two terms

Factor them out

$(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)$

$2x^2(6x-1) + 3(6x-1)$

Thus option A is correct

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