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taurus [48]
3 years ago
12

Triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

the answer should be r

Step-by-step explanation:

Illusion [34]3 years ago
5 0

Answer:

R

Step-by-step explanation:

Law of cosine expression for the triangle will be

q² = r² + p² - 2 (rp) cos Q

going by the equation r and p is given and Q is included then we can calculate q which corresponds tor R which faces or is subtended by angle Q. p correspond to RQ and r correspond to PQ

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Please help!!! Will mark BRAINLIEST!!!!
Bond [772]

In an equilateral triangle, the measure of each angle is 60 degrees. Then the value of x and y is 17/3 and 65.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

In trianlge ΔMNP, PM = 3x - 4, MN = 14, ∠N = 5y - 5.

In an equilateral triangle, all the sides and all the angles are equal.

MN = NP = PM

∠M = ∠N = ∠P

Then we have

   PM = MN

3x - 4 = 14

      x = 17/3

We know in an equilateral triangle, the measure of each angle is 60 degrees. Then we have

    ∠N = 60

5y - 5 = 60

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More about the triangle link is given below.

brainly.com/question/25813512

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2 years ago
Select the choice that translates the following verbal phrase correctly to algebra: the product of k and m
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5 0
3 years ago
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Solve x4 – 17x2 + 16 = 0.<br> Let u =<br> Select all of the zeroes of the function. i i
Soloha48 [4]

Solve \ x^4 - 17x^2 + 16 = 0

To solve this equation , we need to write it in quadratic form

ax^2+bx+c=0

To get the equation in quadratic form we replace x^2 with u

x^2 = u

x^4 - 17x^2 + 16 = 0 can be written as

(x^2)^2 - 17x^2 + 16 = 0, Replace u for x^2

So equation becomes

u^2 - 17u + 16 = 0

Now we factor the left hand side

-16  and -1  are the two factors whose product is +16  and sum is -17

(u-16) (u-1) = 0

u -16 = 0  so u=16

u-1 =0  so u=1

WE assume u = x^2, Now we replace u with x^2

u = 16 so \ it \ becomes \ x^2 =16

Now take square root on both sides , x= +4  and x=-4

u = 1 so \ it \ becomes \ x^2 =1

Now take square root on both sides , x= +1  and x=-1

So zeros of the function are -4, -1, 1, 4


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3 years ago
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Find the area of each triangle then and them together, so:

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3 years ago
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I need help wit 5/2 divided by 5/7 =
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Answer:

7/2

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