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timurjin [86]
3 years ago
8

Consider the geometric sequence 16, 8, a, 2, b, ... (a) Write down the common

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Find the common ratio by dividing.

16 / 8 = 2

8 / a = 2

2 / b = 2

The common ratio is 2.

Since we need to find the values of a and b, use the common ratio to solve for them.

8 / 2 = 4 (a)

2 / 2 = 1 (b)

Now, we know that first 5 terms.

We can solve for the 8th term using the previous terms and the common ratio.

6th term: 1 / 2 = 0.5

7th term: 0.5 / 2 = 0.25

8th term: 0.25 / 2 = 0.125

Part A: 2

Part B: a = 4, b = 1

Part C: 0.125

Best of Luck!

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SOS I need help with this question
Dima020 [189]

Answer:

1) (2x - 3)(x + 5)

2) 1.5, -5

3) Open upwards from both ends

4) Minimum

Step-by-step explanation:

Step 1:

The given polynomial is:

2x^{2}+10x-3x-15

Taking out commons, we get:

2x(x+5)-3(x+5)\\\\ =(2x-3)(x+5)

This is the factorized form of the polynomial.

Step 2:

The zeros of the functions occur when the function is equal to zero.

i.e.

(2x-3)(x+5)=0\\\\ \text{According to the zero product property}\\\\ 2x-3=0, x+5=0\\\\ x =\frac{3}{2}=1.5, x = -5

This means, the zeros of the polynomial are 1.5 and -5

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The end behavior of a graph depends on its degree and the sign of leading coefficient. Since the degree is even and the coefficient is positive the graph of the polynomial will opens upwards from left and right side.

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The given polynomial is a quadratic function with positive leading coefficient. Since it open vertically upwards, its vertex will be the lowest most point. So, the vertex will be the minimum of the function.

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