Answer:
The answer to this question is "the mall"
Step-by-step explanation: .
I got confused with the problem I just divided and the answer is 85 if you need anything else and if I did something wrong go to my comment section and let me know
Answer:
74%
Step-by-step explanation:
Let the weight of price = y%
The weight of quality = 2y%
The weight of delivery reliability = 2y%
Since the sum total of the weights is 100, it implies that:
y% + 2y% + 2y% = 100%
5y% = 100%
y = 100/5
y = 20
So the respective weights are as below:
Price = 20%
Quality = 40%
Delivery reliability = 40%
Weight score = score x category weight
For the supplier:
Price score = 40
Quality score = 90
Delivery reliability score= 75
Overall weighted score = (Price score x Price weight) + (Quality score x Quality weight) + (Delivery reliability score x delivery reliability weight)----- (1)
Substituting into (1), we have :
Overall weighted score = (40 x 20%) + (90 x 40%) + (75 x 40%)
= 8 +36 +30
= 74%
Answer:
A = 1.231413522
Step-by-step explanation:
Did mafs
Answer:
84 child tickets were sold
Step-by-step explanation:
Had they all been adult tickets, revenue would have been ...
$9.80 × 147 = $1440.60
It was less by ...
$1440.60 -1054.20 = $386.40
The child's ticket costs less by ...
$9.80 -5.20 = $4.60
so there must have been $386.40/$4.60 = 84 child tickets sold.
__
Replacing an adult ticket with a child ticket reduces the revenue by $4.60 without changing the number of tickets sold.
_____
You can let c represent the number of child tickets sold. Then (147 -c) is the number of adult tickets sold, and total revenue is ...
5.20c + 9.80(147 -c) = 1054.20
-4.60c +1440.60 = 1054.20 . . . . simplify
-4.60c = -386.40 . . . . . . . . . . . . . subtract 1440.60
c = 386.40/4.60 = 84
