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3 years ago

7

The drama club at a local high school sells adult, teen, and child tickets for a school play. The matrix below represents the ti

ckets sold and the total cost of the tickets for three performances.

1 answer:

8090 [49]3 years ago

8 0

Answer:

a is the correct answer in e2020

Step-by-step explanation:

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A bin of 50 manufactured parts contains 3 defective parts and 47 non-defective parts. A sample of size 6 parts is selected from

lyudmila [28]

Answer:

535,095 different samples of size six that contain exactly 2 defective parts.

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

As the order of the parts is not important, the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many different samples are there of size six that contain exactly 2 defective parts?

2 defective from a set of 3, and 4 non-defective from a set of 47. So

$D = C_{3,2}*C_{47,4} = \frac{3!}{2!1!}*\frac{47!}{4!43!} = 535095$

535,095 different samples of size six that contain exactly 2 defective parts.

What is the probability that a sample contains exactly 2 defective parts?

The total number of samples is:

$T = C_{50,6} = \frac{50!}{6!44!} = 15890700$

Then...

$p = \frac{D}{T} = \frac{535095}{15890700} = 0.0337$

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

8 0

3 years ago

Im really struggling with this, i need A on this test please help me!

taurus [48]

The volume of the square pyramid is 600cm^3

8 0

3 years ago

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How can I factorise (2x cubed - 5x + 3) ?

PilotLPTM [1.2K]

$2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}$

$therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}$

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3 years ago

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Ralph pays his workers $100 each, and labor is the only variable cost. At a quantity of 2000 chickens, how many workers does he

pshichka [43]

Ralph hires 8 workers

What is variable cost ?

Variable costs are expenses that alter as the volume of a good or service a company produces fluctuates. Marginal costs multiplied by the number of units produced make up variable costs. They can be regarded as typical expenses as well. Total cost is divided into two parts: fixed costs and variable costs.

Workers paid = $100

Assuming $1600 is given as a Total cost for the 2000 quantity for chicken and Fixed cost is $800

Total cost = $1600 out of which $800 is the fixed cost

Variable cost = Total cost - Fixed cost

= 1600 - 800

= 800

Numbers of workers hired = Variable cost / Workers pay

Numbers of workers hired = 800 / 100

Numbers of workers hired = 8

Therefore, the number of workers that Ralph hires is 8 workers

To learn more about variable cost from the given link

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6 0

1 year ago

Can someone pls give me the answer to this I need it ASAP

Lady bird [3.3K]

I think it’s A. Remember m stands for the slope of a line

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3 years ago