All categories

3 years ago

Plz help me :( plzzzz

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

CANDIDATE A
18-34 53.7%
35-64 37.3%
65+ 8.9%

CANDIDATE B
18-34 17.6%
35-64 47.1%
65+ 35.3%

You might be interested in

A log-level model relating the natural logarithm of house price, y, to square footage was fit. The fitted model is stack ln (p r

Musya8 [376]

Answer:

$255,331

Step-by-step explanation:

Calculation for the estimated price

ln (price) =11.65 +0.000473*square foot

Square feet =1,692

First step is to find the ln (price)

ln (price) =11.65 +0.000473*1,692

ln (price)=12.450316

Last step is to calculate the Estimated price by using calculator to find the exponential of 12.450316

Estimated price=e^(12.450316)

Estimated price=$255,330.99

Estimated price=$255,331 Approximately

Therefore the estimated price of a house that is 1,692 square feet will be $255,331

7 0

3 years ago

Based on the pattern, which power of 10 would have a value of StartFraction 1 Over 1,000,000 EndFraction?

Hunter-Best [27]

Answer:

powers of 10

Step-by-step explanation:

Simone examined the pattern in the table

7 0

2 years ago

What is the are of the triangle?

lesya [120]

Answer:

the answer would be 4

Step-by-step explanation:

4x2=8

8÷2=4

8 0

3 years ago

Read 2 more answers

A negative number with an absolute value less than 4.

Mars2501 [29]

Answer:

I think its -4.

3 0

3 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago