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Alina [70]
3 years ago
7

2a+3/2 - a-2/3 = a-1/4

Mathematics
2 answers:
lesya [120]3 years ago
7 0

Answer:

No solutions

Step-by-step explanation:

2a+\dfrac{3}{2}-a-\dfrac{2}{3}=a-\dfrac{1}{4}\\a+\dfrac{5}{9}=a-\dfrac{1}{4}\\\dfrac{5}{9}=\dfrac{1}{4}

This equation has no solutions. Hope this helps!

Alinara [238K]3 years ago
4 0

Answer:

No solution

Step-by-step explanation:

2a+3/2 - a-2/3 = a-1/4.

2a- a +3/2 - 2/3 = a-1/4. Add like terms

a + 5/6 = a - 1/4. Variables and numbers on diferent sides

-a. -5/6. -a. -5/6

0 = -13/12

No solution because there are no a's that can make the equation true

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Integration will be ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c  .

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dx = 9 secθ tanθ dθ

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Substituting values in  ∫ 1 dx / ( x^{2} - 81 ) ,

∫ (9 secθ tanθ ) dθ / ( 9 tanθ )

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Rowena can paint a room in $14$ hours, while Ruby can paint it in $6$ hours. If Rowena paints for $x$ hours and Ruby paints for
miv72 [106K]

Question

Rowena can paint a room in 14 hours, while Ruby can paint it in 6 hours. If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting, while if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room. Find the ordered pair (x,y)

Answer:

(x, y) = (231/40, 21/40)

where x = 231/40

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Step-by-step explanation:

From the question, we are told:

Rowena can paint a room in = 14 hours

Ruby can paint it in = 6 hours.

This means

In one hour.

Rowena can paint = 1/14 of the room

Ruby can paint =1/6 hour of the room

From the question, we are told that :

If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting

This is represented mathematically as:

(1/14)(x) + ( 1/6)(y) = 1/2...... Equation 1

Also we were told that:

if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room

(1/14)(y) + (1/6)(x) = 1 .......... Equation 2

Bringing the two equations together, we have:

(1/14)(x) + ( 1/6)(y) = 1/2 ....... Equation 1

(1/14)(y) + (1/6)(x) = 1 ............ Equation 2

We find the Lowest common multiple of the numerator 14 and 6 = 42. Hence, we multiply both equations through by 42

3x + 7y = 21 ....... Equation 3

7x + 3y = 42 ......... Equation 4

To solve for x and y in Equation 3 and 4 we would be using the Elimination method

21x + 49y = 147 .......... Equation 5

21x +9y = 126 ........... Equation 6

21x + 49y = 147 .......... Equation 5

-(21x +9y = 126) ........... Equation 6

40y = 21

y = 21/40

To get the value of x , we would substitute 21/40 for y in Equation 3

3x + 7y = 21 ....... Equation 3

3x + 7(21/40) = 21

3x + 147/40 = 21

3x = 21 - 147/40

3x = 693/40

x = (693/40) ÷ 3

x = 693/40 × 1/3

x = 693/120

x = 231/40

Therefore, (x, y) = (231/40, 21/40)

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