Answer:
2x² + 13x + 15
Step-by-step explanation:
| 2x | 3
x | 2x*x = 2x² | 3*x = 3x
5 | 2x*5 = 10x | 3*5 = 15
We have, 2x² + 3x + 10x + 15
Combining like terms, we would have the final expression as:
2x² + 13x + 15
Answer:
5=y-intercept
Step-by-step explanation:
the y intercept point is when y has a number but x is 0 so we see what is y (f(x)) and it is 5
Answer:
2ITR/KVJFCIUYBDTR67E4VHJN, BHJYUG76T89O;LXCS,DVTI9R0OPE;'
Step-by-step explanation:
Answer:
x = 15
Step-by-step explanation:
We want to solve for x in 3*(2x + 5) = 3x + 4x
First simplify.
3*(2x + 5) = 7x
Next, distribute the 3.
3*2x + 3*5 = 7x
6x + 15 = 7x
15 = 7x - 6x
15 = x
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then



has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.