The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
b
Step-by-step explanation:
sorry if wrong dont report
Answer:
471
Step-by-step explanation:
do to the number in the tenths place not being higher than 5 all number past the decimal become zero and the whole number stay the same
Answer:
109.2-23.6 = 85.6
Step-by-step explanation:
use bodmas
B=bracket
O=of or multiplication
D=division
M=multiplication
A=addition
S=subtraction
so when you are opening a bracket you multipli the number in the bracket with the one outside the bracket
I.E
4×27.3=109.3
4×5.9=23.6
109-23.6=85.6
