If f(x) = |x| and g(x) = |xl - 4, which translation is applied to f(x) to get g(x)?

irga5000 [103]

64.8%. 12 times 10 is 120. 3 times 4 is 12 so the total area is 108. 108 divided by 100 is 1.08 times 60 is 64.8%

4 0

3 years ago

A poll was conducted during the final game of the basket season to determine whether fans wanted to see the defending champions

andrew-mc [135]

If I did this right the answer should by: The results are statistically significant at the 0.05 level of significance in showing that the proportion of people in rural areas who want the defending champions to win the game is different than the proportion of people in urban areas.

5 0

2 years ago

Help, I tried it, but I keep getting the wrong answers

Aneli [31]

Answer:

my answer would be that

x = 17.91cm

(i'm not sure about it either but it's worth a try) !!

Step-by-step explanation:

so first off, using the equation given,

" c² = a² + b² — 2ab cos C "

we substitute the values in as,

a = 16

b = 30

then for C is the angle given, which is 30°

so the equation is now,

c² = (16)² + (30)² — 2(16)(30) cos 30°

now, you solve the two squared numbers and the back equation, also known as " 2ab cos C " with your scientific calculator.

so it now equals to,

c² = 256 + 900 — 960(0.87)

c² = 320.8

at last, when you have " c² = 320.8 " ,

remember to square root the answer so you have a smaller value.

so,

c equals to

$\sqrt{320.8}$

your final answer for the x value will be 17.91

(i hope this helps!)

8 0

3 years ago

A bird flies 50km everyday to collect food for his offspring and 20km to drink water. To fly this distance takes him 1 hour and

dem82 [27]

Answer:

42km/h

Step-by-step explanation:

70km=100 minutes

7km= 10min

42km=60min

42km/h

7 0

1 year ago

he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w

stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666 )

Step-by-step explanation:

Given the data in the question;

Sample 1 Sample 2

x"₁ = 259.23 x"₂ = 365.12

s₁ = 34.713 s₂ = 48.297

n₁ = 5 n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

$S_p^2$ = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

$S_p^2$ = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

$S_p^2$ = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [ 4 + 9 ]

$S_p^2$ = [ 4819.9692 + 20993.4 ] / [ 13 ]

$S_p^2$ = 25813.3692 / 13

$S_p^2$ = 1985.64378

Now the Standard Error will be;

$S_{x1-x2$ = √[ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

$S_{x1-x2$ = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

$S_{x1-x2$ = √[ 397.128756 + 198.564378 ]

$S_{x1-x2$ = √595.693134

$S_{x1-x2$ = 24.4068

Critical Value = $t_{\frac{\alpha }{2}, df$ = $t_{0.05, df=13$ = 1.771 { t-table }

So,

Margin of Error E = $t_{\frac{\alpha }{2}, df$ × [ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666 )

3 0

3 years ago