Find the volume. Please
1 answer:
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>
<h3><em>Good</em><em> </em><em> </em><em>luck</em><em> </em><em>on </em><em>your</em><em> </em><em>as</em><em>signment</em></h3><em>-pragya~</em><em>~</em>
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Answer:
<em>120 degrees</em>
Step-by-step explanation:
Find the diagram attached.
From the diagram;
Interior angles are m∠BCA and m∠ABC
Exterior angle is m∠DAB
The sum of interior angle of the triangle is equal to exterior
m∠BCA +m∠ABC =m∠DAB
Given
m∠ABC = 70
m∠BCA =50
m∠DAB = 70 + 50
m∠DAB = 120 degrees
<em>Hence the measure of m∠DAB is 120 degrees</em>
Let
x---------> first positive integer
x+1------> second positive integer
x+2-----> third positive integer
we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0
using a graph tool-------> <span>I solve the quadratic equation
</span>see the attached figure
the roots are
x1=-10
x2=7
the answer is
first positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9
x---------> first positive integer
x+1------> second positive integer
x+2-----> third positive integer
we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0
using a graph tool-------> <span>I solve the quadratic equation
</span>see the attached figure
the roots are
x1=-10
x2=7
the answer is
first positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9
<h3>Answer: 80.94 square cm</h3>
==================================================
Work Shown:
Area of parallelogram = base*height
Area of parallelogram = 11.4*7.1
Area of parallelogram = 80.94 square cm
-------------
notes:
- The base and height always form a 90 degree angle (as shown by the small square marker).
- The side length of 8.9 cm is never used.
- We can write "square cm" as "cm^2" or