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ValentinkaMS [17]
2 years ago
5

Andy takes a computer course exam He scores 53 marks out of 75. the table shows the result obtained based on the percentage in t

he exam

Mathematics
2 answers:
Rashid [163]2 years ago
6 0

Answer:

i think it is

a)70.666

b)merit

Step-by-step explanation:

xeze [42]2 years ago
4 0
A) 70.7%
Explanation 53/75 * 100
B) Merit
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75 is the median of the data set 68, 67, 75, 73, 72.
Ludmilka [50]
Truee is right you got it dude
4 0
2 years ago
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What are the roots of the quadratic equation below 2x^2-5x-1=0
PilotLPTM [1.2K]

Answer:

roots=(5±sqrt(33))/4

Step-by-step explanation:

roots=(-b±sqrt(b^2-4ac))/2a

roots=(-(-5)±sqrt(25+8))/(2*2)

roots=(5±sqrt(33))/4

roots=(5+sqrt(33))/4 and (5-sqrt(33))/4

7 0
2 years ago
Im going to die dumb please help
vova2212 [387]

Answer:

im thinking it's experimental or sample space but go with your mindset

Step-by-step explanation:

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8 0
2 years ago
6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

  • Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;

  • Paul's distance east =  15 km × cos(37°) ≈ <u>11.98 km</u>

Pau's distance travelled in the south direction relative to the starting point

is given by the vertical distance travelled relative to the x-axis, which is

given as follows;

Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>

Learn more about bearings in trigonometry here:

brainly.com/question/23427938

5 0
2 years ago
The dimensions of a rectangles are 8cm and 12cm. What is the ratio of its length to its perimeter?
kari74 [83]

Answer:

Dimensions = 8 CM and 12 CM

length = 12 CM

width = 8 cm

perimeter = 2 ( length + width)

= 2( 12 + 8)

= 2 ( 20)

= 40 CM

ratio = 12/40

= 6/20

= 3/10

<h2>= 3 : 10 </h2>
3 0
1 year ago
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