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3 years ago

~I will mark as BRANLIEST and give you 55 points if you answer correctly.

Mathematics

2 answers:

kompoz [17]3 years ago

8 0

Answer:

(4,-2)

Step-by-step explanation:

The equation for the graphed line is $y=\frac{1}{2} x-4$ as it has a slope of $\frac{1}{2}$ and a y-intercept of -4.

Now that we have the two equations, we can set them equal to each other to find the x-value at which they intersect

$\frac{1}{2} x-4=-x+2$

First, we can add 4 to each side

$\frac{1}{2} x=-x+6$

Then we can add x to each side

$\frac{3}{2} x=6$

Now we need to divide both side by $\frac{3}{2}$ , which is the same thing as multiplying by $\frac{2}{3}$

$x=6*\frac{2}{3} \\\\x=\frac{12}{3} \\\\x=4$

Now that we have the x-value, we can plug it into one of the equations to see the y-value for where they intersect.

$y=-x+2\\\\y=-(4)+2\\\\y=-2$

This means that the coordinates for the intersection of these two lines would be $(4,-2)$

Dmitrij [34]3 years ago

5 0

Answer:

The lines would intersect at: (6, -4)

Step-by-step explanation:

I graphed both lines.

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The price of 7 cell phones, 9 TV sets and 12 air-conditioners is

mezya [45]

here, 7 cellphone,9 Tv, 12airconditioners = 8723

5 cellphone,7 Tv, 12airconditioners = 6523

or, 7,9,12=8723

-5,7,9=6523

______________

2,2,3=2191

then,

to make 4 cellphone , 4 tv set , 6 air conditioners add twice the answer ,

2,2,3=2191

+2,2,3=2191

____________

4,4,6=4382

hence,

the price of 4 cellphone , 4 tv set and 6 air conditioners is 4382 #

solved by

<h3> pratik</h3>

6 0

3 years ago

There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of

Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

$AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta$ (1)

Where:

$AC$ - The distance from A to C, measured in miles.

$AB$ - The distance from A to B, measured in miles.

$BC$ - The distance from B to C, measured in miles.

$\theta$ - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

$AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta$

$\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}$

$\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right)$ (2)

If we know that $BC = 7\,mi$ , $AB = 8\,mi$ , $AC = 5\,mi$ , then the bearing from island B to island C:

$\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]$

$\theta \approx 38.213^{\circ}$

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0

3 years ago

The test scores you end up having in geometry class are 81 and 87. What possible scores can you earn on your next test to have a

Zigmanuir [339]

Answer:

88, 89, 90, 91, 92? idrk

4 0

3 years ago

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Hunter-Best [27]

Answer:

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Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A line passes through (-8,3) and (-6,4).What is the equation of the line?

Komok [63]

Answer: The equation of the line that passes through the points

(-8,3) and (-6,4)

y=1/2x+7

Step-by-step explanation: First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-8,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-8 and y1=3.

Also, let's call the second point you gave, (-6,4), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-6 and y2=4.

Now, just plug the numbers into the formula for m above, like this:

4 - 3

-6 - -8

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-8,3). When x of the line is -8, y of the line must be 3.

(-6,4). When x of the line is -6, y of the line must be 4.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-8,3) and (-6,4).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-8,3). y=mx+b or 3=1/2 × -8+b, or solving for b: b=3-(1/2)(-8). b=7.

(-6,4). y=mx+b or 4=1/2 × -6+b, or solving for b: b=4-(1/2)(-6). b=7.

See! In both cases we got the same value for b. And this completes our problem.

7 0

2 years ago