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Marianna [84]
3 years ago
14

Mixed Review for Finding Slope

Mathematics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

1) slope of the line m = \frac{1}{4}

2) slope of the line     m = \frac{11}{8}

3) slope of the line   m =2

4) slope of the line   m = \frac{-8}{3}

5) slope of the line m =7

Step-by-step explanation:

1)

Given points are  (4,5) and (-4,3)

slope of the line  Formula

             m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }

            m = \frac{3 - 5 }{-4-4 } = \frac{-2}{-8} = \frac{1}{4}

            m = \frac{1}{4}

2)

Given points are (-2,-4) and (6,7)

slope of the line  Formula

             m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }

            m = \frac{7 - (-4) }{6-(-2) } = \frac{11}{8}

            m = \frac{11}{8}

3)

Given points are (2, -4) and (10,12)

slope of the line  Formula

             m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }

            m = \frac{12 - (-4) }{10-(2) } = \frac{16}{8} =2

            m = 2

4) Given points are

      (1/2,2) and (1, 2/3)

  slope of the line  Formula

             m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }

            m = \frac{\frac{2}{3}  - (2) }{1-(\frac{1}{2} ) } = \frac{\frac{-4}{3} }{\frac{1}{2} }

            m = \frac{-8}{3}

5)

Given points are

      (1/4,5) and (5/4 , 12)

  slope of the line  Formula

             m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }

            m = \frac{12-5}{\frac{5}{4} -\frac{1}{4} } = \frac{7}{\frac{4}{4} } = 7

            m = 7

                     

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RSB [31]
Isolate the variable by dividing each side by factors that don't contain the variable.

x= 13/4 - y/4



If you are solving for x (only)
X = 45/4 - y/4

If you are solving for y (only)
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6 0
4 years ago
Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample
adelina 88 [10]

Answer:

\sigma = 12.5 ---- sample standard deviation

\sigma^2 = 157.2 ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

x_1 = \frac{56 + 64}{2} = 60

x_2 = \frac{65 + 73}{2} = 69

And so on

So, the table becomes:

\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}

Calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}

\bar x = \frac{4191}{55}

\bar x = 76.2

The variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}

\sigma^2 = \frac{8488.8}{54}

\sigma^2 = 157.2

The sample standard deviation is:

\sigma = \sqrt{\sigma^2

\sigma = \sqrt{157.2

\sigma = 12.5

Solving (b): The sample variance

In (a), we calculate the sample variance to be:

\sigma^2 = 157.2

6 0
3 years ago
I want to do this problem in product standard form (5i-3)(2i+1)
Ilia_Sergeevich [38]
<h3>Answer:    -13 - i</h3>

=======================================

Work Shown:

Let x = 5i-3

That allows us to go from (5i-3)(2i+1) to x(2i+1)

Distribute the x through: x*(2i) + x*(1) = 2i*x + x = 2i(x) + 1(x)

Now we replace every x in 2i(x) + 1(x) with 5i-3, and then we distribute a second time

2i(x) + 1(x) = 2i(5i-3) + 1(5i-3)

2i(x) + 1(x) = 2i(5i)+2i(-3) + 1(5i)+1(-3)

2i(x) + 1(x) = 10i^2 - 6i + 5i - 3

2i(x) + 1(x) = 10(-1) - i - 3

2i(x) + 1(x) = -10 - i - 3

2i(x) + 1(x) = -13 - i

Therefore, (5i-3)(2i+1) = -13 - i

The result is in a+bi form where a = -13 and b = -1.

------------------

An alternative method is to use the box method. This is where you set up a grid that helps you multiply out (5i-3)(2i+1)

See the diagram below.

Each of the 4 red terms in the boxes represents the result of multiplying the outer blue and green terms. Example: 5i times 2i = 10i^2 in row1, column1.

7 0
3 years ago
the area of a rectangle is 35 square yards the length of one side is 5 yards what is the length of the other side
Aleonysh [2.5K]
Area = length multiplied by width
35=5x
The other length is 7 yards. 
5 0
3 years ago
Ashop has 3276 coat hangers. They store the coat hangers in boxes of 13. The shop also has 198 boxes of T-shirts. How many boxes
Dennis_Churaev [7]

Answer:

450 boxes

Step-by-step explanation:

3276÷13= 252

252+198=450. I hope this helps!*

8 0
3 years ago
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