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Setler79 [48]
3 years ago
11

the area of a rectangle is 35 square yards the length of one side is 5 yards what is the length of the other side

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
5 0
Area = length multiplied by width
35=5x
The other length is 7 yards. 
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What is the solution to the inequality below ?
Vlad1618 [11]
[tex]Domain:x\geq0\\\\\sqrt{x}\leq5\ \ \ \ |square\ both\ sides\\\\x\leq25[tex]

Answer: B. 0 ≤ x ≤ 25
8 0
3 years ago
You bought a car that was $25500 and the value depreciates by 4.5% each year.
nikklg [1K]

Answer:

(a) 20256.15625

(b) 17642.78546

Step-by-step explanation:

(a) There's a formula for this problem y = A(d)^t where, A is the initial value you are given, d is the growth or decay rate and t is the time period. So, in this case, as the car cost is decreasing it is a decay problem and we can write the formula as such; y = A(1-R)^t

So, in 5 years the car will be worth, 25500(1-4.5%)^5 or 20256.15625 dollars

(b) And after 8 years the car will be worth 25500(1-4.5%)^8 or 17642.78546 dollars.

7 0
3 years ago
An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
EleoNora [17]

Answer:

Rachel

Step-by-step explanation:

We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.  

That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that

mean - x*s = t

For Rachel we have

11 - x*3 = 8, so x = 1.  

Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class

For Kenji we have

9 - x*2 = 8.5, so x = 0.25

Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class

For Nedda we have

7 - x*4 = 8, so x = 0.25

Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.

As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.

8 0
3 years ago
Which point is in the solution set of the given system of inequalities 3x+y&gt;-3,x+2y&lt;4
Dima020 [189]
Step 1. Solve both inequalities for y:
3x+y\ \textgreater \ -3
y\ \textgreater \ -3x-3

x+2y\ \textless \ 4
2y\ \textless \ -x+4
y\ \textless \ - \frac{1}{2} x+2

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines -3x-3 and - \frac{1}{2} x+2:

y=-3x-3 (1)
y=- \frac{1}{2} x+2 (2)

Replace (1) in (2):
-3x-3=- \frac{1}{2} x+2
Solve for x:
\frac{5}{2} x=-5
x=-2 (3)

Replace (3) in (1):
y=-3x-3
y=-3(-2)-3
y=6-3
y=3

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

4 0
3 years ago
Read 2 more answers
What is 60/13 as a decimal?
love history [14]
The correct solution to the problem 60/13 is 4.61
7 0
3 years ago
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