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Alchen [17]
3 years ago
7

The “prize” discovery at the Nansen Crater was olivine. What valuable information did NASA learn from this sample?

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

1. One valuable information NASA learnt from the sample of olivine is that some parts of Mars had been dry over a long period of time.

2. The two materials are:

i. Oxygen supply.

ii. Air temperature and pressure regulation.

Step-by-step explanation:

NASA went on a research mission on mars and observed the Nansen crater, and discovered the olivine in the crater. It was learnt from the sample of olivine that parts of Mars had been dry over a long period of time.

2. The Personal Life Support System is a part of the suit used by astronauts to create an artificial habitat condition for their body system. This suit contains some materials that preserve their lives in space. The major materials in the suit are; oxygen (for breathing purpose) and air temperature and pressure regulation.

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Shtirlitz [24]

Answer:

1050

Step-by-step explanation:

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wool (3x3) x 94 =846

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7 0
2 years ago
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in a random sample of 45 endangered species, 12 are categorized as vulnerable, 11 are categorized as endangered, and 22 are cate
horrorfan [7]

The probability that the randomly selected sample is vulnerable or critically endangered is equal to 0.76

The probability can be determined using the following formula;

probability = number of desired events or outcomes ÷ total number of events or outcomes

The total is known to be 45, the favorable or desired outcomes can be calculated as follows;

number of desired outcomes = number of vulnerable species + number of critically endangered species

number of desired outcomes = 12 + 22

number of desired outcomes = 34

Now we calculate the probability by using the above formula;

probability = 34 ÷ 45

probability = 0.76

Therefore, 0.76 is the probability that the randomly selected species is vulnerable or critically endangered.

Although a part of your question is missing, you might be referring to this question:

In a random sample of 45 endangered species, 12 are categorized as vulnerable, 11 are categorized as endangered, and 22 are categorized as critically endangered. what is the probability that a randomly selected species from this sample is vulnerable or critically endangered? group of answer choices

11/45

0.24

0.83

0.76

12/45

To learn more about probability, click here:

brainly.com/question/24756209

#SPJ4

8 0
1 year ago
The position "d" of a bicyclist (measured in kilometers) is a linear function of time "t" (measured in minutes). At time t=6 min
vladimir1956 [14]

I am continuously trying to answer but it says my answer has something inappropriate! I will try in comments section!

4 0
3 years ago
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spayn [35]
Can you translate so I can help you out
4 0
3 years ago
Hey um i need help answering this one question. The question is: If x2 = 50, what is the value of x?
Igoryamba
Take the square root of both sides

x^2=50

x=±√50

x=-√50 and √50

x≈-7.07 and 7.07
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3 years ago
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