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gregori [183]
4 years ago
6

A locker combination has three nonzero digits, and the digits cannot be repeated. The first two digits are 1 and 2. What is the

probability that the third digit is 3?
Mathematics
1 answer:
trasher [3.6K]4 years ago
4 0

Answer:

Approximately 14% or 1/7

Step-by-step explanation:

To solve this problem, first find the ratio of 3 to the possible numbers.

There are 9 possible digits in one space on a non-zero combination lock. However, digits cannot be repeated, and 1 and 2 are already taken. Therefore, there are 7 possible digits (9 - 2 = 7). Therefore, the ratio of getting a 3 to possible digits is 1:7, as there is 1 '3' and 7 others.

As a fraction, 1:7 is 1/7. As a percentage, 1/7 is about 14%. Therefore, there is approximately a 14% chance that the third digit will be 3.

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What value of m does the graph y = 18x2 + mx + 2 have exactly one x-intercept?
Vlada [557]
To get the graph to have one x-intercept, we must find the m value where the discriminant of the equation will equal 0.

The discriminant for a graph with one x-intercept is found with the following formula:

b^2 - 4ac = 0

Plug in the values of the equation into this formula:

\text{a = 18, b = m, c = 2}
m^2 - 4(18)(2) = 0
m^2 - 144 = 0

Add 144 to both sides:

m^2 = 144

Square root both sides to get m by itself:

\sqrt{144} = \pm 12
m = 12, \ m = -12

In order for the graph to have one x-intercept, m must equal -12 or 12.
7 0
4 years ago
You have climbed to the top of a tall tree. When you get to the top, you use your clinometer to discover that the angle between
GuDViN [60]

Answer:

F. 34.64 m

Step-by-step explanation:

The measurements given in the question are;

The angle (of depression) given by the clinometer, θ = 30°

The horizontal distance of the lunchbox from the tree, d = 20 meters

The height (how tall) of the tree = Required

Let the height of the tree be assumed to be perpendicular to the ground, noting that the horizontal distance from the lunchbox to the tree is a straight line, let <em>l</em> represent the line of sight from the top of the tree to the lunchbox, and let <em>h </em>represent the height of the tree we have;

The line of sight to the lunchbox, <em>l</em>, the height of the tree, <em>h</em>, and the horizontal distance of the lunchbox from the base of the tree form a right triangle

The height of the tree is the adjacent leg to the given angle by the clinometer

Using trigonometric ratios, we have;

tan(30°) = d/h

∴ tan(30°) = (20 m)/h

h = (20 m)/tan(30°) ≈ 34.64m

The height of the tree, h ≈ 36.64 m.

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3 years ago
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Nady [450]

Step-by-step explanation:

firstly there is hole in the ozone

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6 0
3 years ago
I can’t figure this out . I’m not good at math.
Romashka [77]

Answer: B

Step-by-step explanation:

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6 0
3 years ago
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Question 8 of 12<br> Use the distributive property to remove the parentheses.<br> 3 (3+x)
Vilka [71]

Answer:

9+3x

Step-by-step explanation:

3 (3+x)

Distribute

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3 0
3 years ago
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