Question 8 of 12 Use the distributive property to remove the parentheses. 3 (3+x)
1 answer:
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Here you go. This is the graph of the function:
y - 3 = 2(x - 5)
Answer:
Step-by-step explanation:
Hey there!
Standard form is what this equation is in
Standard form is this:
So order to complete the square, you need to take the term out of the equation, divide it by two, and then square it
In this case, the term is 8
We need to divide 8 by 2 ---> 4
Then square 4 ---> 16
So now you should add 16 to both sides
Now you can simplify the LHS
Now you subtract 16 from both sides
So this is as far as you can go since you cannot take the square root of a negative number
Answer:
a) 'X' be the random variable in discrete distribution
b) <em> The value of y = 0.2</em>
<em>c) The mean value or Expectation value</em>
<em>E (X) = 1.25</em>
<em>d) </em>
<em>The variance σ² of the discrete distribution function is</em>
<em>Variance ( V(x)= 1.2875</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given data
x : 0 1 2 3 4
P(x) : 0.30 0.35 y 0.10 0.05
a)
Let 'X' be the random variable in discrete distribution
Given data is discrete distribution
<em>i) If the numbers </em> for all values of 'i'
ii) ∑P(x) = 1
Given data <em> </em> for all values of 'i'
∑P(x) = 1
0.30+0.35+y+0.10+0.05 =1
y + 0.8 = 1
y = 1 -0.8 = 0.2
<em>b) The value of y = 0.2</em>
<u><em>Step(ii):-</em></u>
<u><em>Expectation:</em></u>
Given data
x : 0 1 2 3 4
P(x) : 0.30 0.35 0.2 0.10 0.05
<em>The mean value or Expectation value</em>
<em>E (x) = ∑ x p ( X = x)</em>
<em> = 0 × 0.30 + 1 × 0.35 + 2 × 0.2 + 3 × 0.10 + 4 × 0.05</em>
<em> = 0 + 0.35 + 0.4 + 0.30 + 0.2</em>
<em> = 1.25</em>
<u><em>Variance of X</em></u>
The variance σ² of the discrete distribution function is defined by
σ² = ∑ x² p(x=x) - μ²
= 0× 0.30 + 1² × 0.35 + 2²× 0.2 +3²× 0.10 + 4²× 0.05 - (1.25)²
= 0 + 0.35 + 0.8 + 0.9 + 0.8 - 1.5625
= 1.2875
<u><em>conclusion:-</em></u>
<em>The mean value or Expectation value = 1.25</em>
<em>The variance σ² of the discrete distribution function</em>
<em> V(X) = 1.2875</em>