<span>In order to ensure that the scientific process remains upheld, and that our knowledge continues to grow, it is crucial to keeping an open mind when analyzing various experiments, due to the fact that new and acquired knowledge can better help provide more accurate results.</span>
Answer:

Explanation:
Given


Each term after the second term is the average of all of the preceding terms
Required:
Explain how to solve the 2020th term
Solve the 2020th term
Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.
The very first thing to do is to solve for the third term;
The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term
<em>This is proved as follows;</em>
From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

<em>Assume n = 3</em>

<em>Multiply both sides by 2</em>


<em>Assume n = 4</em>


Substitute 



Assume n = 5


Substitute
and 



<em>Replace 5 with n</em>

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

Hence,

Calculating 



Recall that 

Answer:
i connot answer your question sorry po