Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
21.25
Step-by-step explanation:
diagonal is 21.25
the area is 216.75
the perimeter is 59.5
Answer:
36
Step-by-step explanation:
X/100% x 140 = 50.4
X x 140 = 50.4 x 100
X x 140 = 5040
X = 5040/140
X = 36
Answer:
1.9
Step-by-step explanation:
you divide 12 by 2 then divided that by pi
Answer:
7/25 sin= opposite/hypotenuse
Step-by-step explanation:
I'm just good like that.
