All categories

3 years ago

Math plzzz help alot of points

Mathematics

2 answers:

navik [9.2K]3 years ago

8 0

Answer:

a=36

b=6

c=1000

d=10

Step-by-step explanation:

sqrt{36}=6

3sqrt{1000}=10

Mars2501 [29]3 years ago

7 0

Answer:

b) 6 ; d) 10

Step-by-step explanation:

It is correct 100%

You might be interested in

What does it mean to solve an equation

12345 [234]

In Middle School math, it means to find out what number ' x ' must be in order for the equation to be a true statement. In middle school, it can only be one number.

7 0

3 years ago

Read 2 more answers

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

4 years ago

3х - бу = -24 how do I get the x and y intercepts?

svetoff [14.1K]

Answer:

x (8, 0) y (0, -4) I think

6 0

3 years ago

Find domain of 1-x if x is less than or equal to 1

Fiesta28 [93]

The domain of a function is the complete set of possible values of the independent variable. In plain English, this definition means: The domain is the set of all possible x-values which will make the function "work", and will output real y-values.
so the given is already the domain
x is less than or equal to 1

4 0

3 years ago

I think its D, am I correct? plzz answer quickly!

serg [7]

The answer is the second option:
6/h = 10/40

4 0

3 years ago