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laila [671]
3 years ago
6

Find the smaller consecutive integers if the sun is smaller and twice the larger is -4

Mathematics
1 answer:
lakkis [162]3 years ago
4 0
Let the intgers be n and n+1. Then:-

n + 2(n + 1) = -4
3n + 2 = -4
3n = -6
n = -2

Smallest integer is - 2. 

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What number are we going to compare bro?
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3 years ago
As a television executive, you have been given 12 shows to choose from to run during your prime time slots each week. If you hav
Oksanka [162]

Answer:

You can create the schedule for the week in 19,958,400 ways.

Step-by-step explanation:

The order in which the shows are scheduled is important, which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

How many ways can you create the schedule for the week?

8 shows from a set of 12. So

P_{(12,8)} = \frac{12!}{(12-8)!} = \frac{12!}{4!} = 19958400

You can create the schedule for the week in 19,958,400 ways.

5 0
3 years ago
Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =
Amiraneli [1.4K]

Answer:

5^{-2}

Step-by-step explanation:

5^{(10-12)}

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3 years ago
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worty [1.4K]

2.34567

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5 0
3 years ago
Read 2 more answers
Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0
3 years ago
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