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NikAS [45]
2 years ago
5

For what values of theta(0

Mathematics
2 answers:
Fofino [41]2 years ago
4 0

Answer:

0

Step-by-step explanation:

mihalych1998 [28]2 years ago
4 0

Answer:

D

Step-by-step explanation:

Just took the test on Edge 2020

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X^2+6X=16 is a quadratic equation what are the solutions?
IgorC [24]
The answer is 2,-8.
But I am not sure. Hope this will help you!
4 0
3 years ago
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Simplify the following expression. 4a^-2b<br><br> A.) b/4a^2<br> B.)4b/a^2<br> C.)1/4a^b2
Sergio [31]
ANSWER

The correct answer is B

\frac{4b}{ {a}^{2} }


EXPLANATION

The given exponential expression is

4 {a}^{ - 2} b

We can rewrite this as,

4b \times  {a}^{ - 2}

We need to simplify to obtain a positive index, so we apply the following property,


{a}^{ - m}  =  \frac{1}{ {a}^{m} }

This implies that,


4b \times  {a}^{ - 2}  = 4b \times  \frac{1}{ {a}^{2} }

This will finally simplify to,

4b \times  {a}^{ - 2}  =\frac{4b}{ {a}^{2} }


Therefore the correct answer is B
6 0
3 years ago
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Anybody know how to do lowest terms and can teach me how to get the answer to lowest terms questions?
Rzqust [24]

Answer:

Step-by-step explanation:

6/9+x=7/10

x=7/10-6/9

when adding fractions both denominators must be equal, we’ll make them 90

x=(7/10)(9/9)-(6/9)(10/10)

x=63/90-60/90

x=3/90, the greatest divisor of 3 and 90 is 3 so divide both the numerator and denominator by 3

x=(3/3)/(90/3)

x=1/30

4 0
2 years ago
​3x-2≤5(x+2) . show all steps please.
Natasha_Volkova [10]

Answer:

-6 ≤x

Step-by-step explanation:

3x-2≤5(x+2)

Distribute

3x-2≤5x+10

Subtract 3x

3x-2-3x≤5x +10-3x  

-2 ≤2x+10

Subtract 10 from each side

-2-10 ≤2x+10-10

-12 ≤2x

Divide by 2

-12/2≤2x/2

-6 ≤x

3 0
2 years ago
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Quadrilateral ABCD with vertices A(-9, 2), B(-8, 8), C(-4, 6), and D(-2, 2) is shown. You want to reflect quadrilateral ABCD in
telo118 [61]

Answer:

See explanation.

Step-by-step explanation:

Graph the quadrilateral. By inspection, you can tell where the midpoint is. (see attachment 1)

Now, I'll draw a line through it. (see attachment 2)

To reflect across a line, think about the points traveling across the line the same number of spaces the point is from the line. For example, point A is three away from the line. So, A' will be 3 away from the other side. The coordinates will be at (-3,2). (see attachment 3).

Do the same for the other points, and you'll have your image.

7 0
2 years ago
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