All categories

2 years ago

Find f(-1) if f(x) = -2x^2 -x

Mathematics

1 answer:

kykrilka [37]2 years ago

3 0

I hope it was helpful to you

if u like follow me

You might be interested in

Carlos has 2,175 marbles in his collection . Emily has 1833 marbles in her collection . Carlos says that he has about 1,000 more

kenny6666 [7]

Carlos is wrong since when subtracted 2175 from 1833 you get 342 so that's about one third of what he said.

5 0

3 years ago

Leah ran 5/7 of a lap and Ryan ran 2/3 of a lap. Who ran farther and by how much?

Goryan [66]

Leah, she ran farther by 1/21

How you get the answer:

5/7
Multiply 7x3 to get the denominator and do the same to the numerator 5x3! Which is 15/21
To get 21 from 2/3 is to multiply 3x7 (denominator) and 2x7 (numerator) to get 14/21

15/21 > 14/21 so Leah ran farther by 1/21

7 0

3 years ago

A) make U subject of the formula E= m/2g(v^2-u^2)

ollegr [7]

Answer:

u = v2−2Egm−−−−−−−√

Step-by-step explanation:

2Eg = 2g (M2g(V2−U2)

2Eg = m(V2 - U2)

2Eg - mV2 - mU2

mU2 = mV2 - 2Eg

mU2m=mV2−2Egm

U2 = mV2−2Egm

= mV2m−2Egm

U2 = V2 - 2Egm

U = V2−2Egm−−−−−−−−√

7 0

2 years ago

Car colors preference change over the years and according to the particular model that the customer selects. In a recent year, 1

Margarita [4]

Answer:

99.05% probabilitiy that at most six cars are black.

Step-by-step explanation:

For each luxury car, there are only two possible outcomes. Either it is black, or it is not black. The probability of a luxury car being black is independent from other luxury cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.1, n = 25$

If 25 cars of that year and type are randomly selected, find the probabilitiy that at most six cars are black.

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X = 3) = C_{25,3}.(0.1)^{3}.(0.9)^{22} = 0.2265$

$P(X = 4) = C_{25,4}.(0.1)^{4}.(0.9)^{21} = 0.1384$

$P(X = 5) = C_{25,5}.(0.1)^{5}.(0.9)^{20} = 0.0646$

$P(X = 6) = C_{25,6}.(0.1)^{6}.(0.9)^{19} = 0.0239$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0718 + 0.1994 + 0.2659 + 0.2265 + 0.1384 + 0.0646 + 0.0239 = 0.9905$

99.05% probabilitiy that at most six cars are black.

7 0

3 years ago

GIVING 100 POINTS

kodGreya [7K]

Answer:This is litr=erally middle school math its so easy

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers