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Shtirlitz [24]
3 years ago
8

One winter night the temperature fell 13 degrees between midnight and 5 A.M. By 9 A.M.the temperature had doubled from what it w

as at 5 A.M. By​ noon, it had risen another 9 degrees to 29 degrees. What was the temperature at​ midnight?
Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer:

23 degrees

Step-by-step explanation:

First, subtract 9 from 29 to find the temperature at 9 A.M. The temperature at 9 A.M. was 20 degrees. The temperature from 5 A.M. doubled to get to the temperature at 9 A.M., so divide 20 by 2. The temperature at 5 A.M. was 10 degrees. The temperature from midnight to 5 A.M. fell 13 degrees, so add 13 to get the temperature at midnight. 13+10=23. It was 23 degrees at midnight.

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Answer:

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Step-by-step explanation:

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olga55 [171]

Answer:

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Step-by-step explanation:

Given:

The radius of the sphere= 1 yard

Volume of a Sphere:

                        \frac{4}{3}* \pi *r^3                                                         :\pi =\frac{22}{7} =3.14

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Surface area of the sphere= 4*\pi* r^2

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Surface area of the sphere up to two decimal places  =12.56 square yards

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