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ahrayia [7]
3 years ago
10

What is 2 log x - logy - 2 log z written as a single logarithm?

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

Log [x^2 / yz^2]

Step-by-step explanation:

2log(x) =log(x^2)

-log(y) = The minus sign means that you can divide it by first log(x^2)

-2log(z) =log(z^2), and the minus sign again means you can divide it by the first log(x^2)

So, the whole thing can be written like this:

Log(x^2) / [log(y)*log(z^2)], OR:

Log [x^2 / yz^2]

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Answer:

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Step-by-step explanation:

Step 1: Given equation: 9=\frac{1}{2} a t^{2}+u t

To get u, by subtraction equality property subtract both sides of the equation by  \frac{1}{2} a t^{2}.

\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}  

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Step 2: By division equality property, divide both sides of the equation by t.

\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}

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Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$.

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$.

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Step-by-step explanation:

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