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3 years ago

I need help Please help.

Mathematics

1 answer:

asambeis [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

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Use the scale of 1cm=45 km

alex41 [277]

Answer:

d = 7.4 cm is the distance between the two cities on the map.

Step-by-step explanation:

Let d = the distance measured on the map in centimeters (cm) between any two locations and let D be the actual distance in kilometers (km) between these same two locations.

Since the scale on the map is 1 cm = 45 km, then the ratio of the distance on the map to the actual distance is equal to 1cm/45 km; therefore the quotient of any measured distance d on the map divided by the corresponding much longer actual distance D would have to maintain (equal) this same ratio; In other words, we can set up the following proportion to solve for d given the actual distance D = 333 km as follows:

1 cm/45 km = d/D

Substituting, we get:

1 cm/45 km = d/333 km

d/333 km = 1 cm/45 km

(d/333 km)(333 km) = (1 cm/45 km)(333 km)

d = (333 km/45 km)(1 cm)

d = 7.4 cm is the distance between the two cities on the map.

Check:

1 cm/45 cm = d/333 km

1 cm/45 cm = 7.4 cm/333 km

1 cm/45 cm = 1 cm/45 km (Therefore, the distance ratio of the map has been maintained

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Answer:

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